Since this is a combination not a permutation problem, (order does not matter) you should use the "n choose k" formula.
C=n!/(k!(n-k)!) where C is the number of unique combinations, n equals the total number of possible choices and k equals the specific number of choices. In this case:
C=9!/(4!(9-4)!)
C=9!/(4!5!)
C=362880/(24*120)
C=362880/2880
C=126
So there are 126 unique ways to pick 4 people from a group of 9 people.
I’m pretty sure it’s median because that’s what you would usually use for outliers.
Answer:
4 1/4
Step-by-step explanation:
BRAINLIEST?!
Answer:
It is already in standard form
Step-by-step explanation:
Four hundred eighty-two and seventy-three thousandths. = 482.073
It is already in standard form
Hope this helps!
Answer:
816 people attended on Saturday night.
Step-by-step explanation: