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pychu [463]
2 years ago
6

John and David graphed a circle with center (-3,1)

Mathematics
1 answer:
mihalych1998 [28]2 years ago
8 0

Neither of them are fully correct because the equation of a circle is:

(x - h) ^{2}  + (y - k) ^{2}  = r ^{2}

h = x value of center coordinate

k = y value of center coordinate

r = radius

Therefore, the correct equation of the circle is:

(x  + 3) ^{2}  + (y - 1) ^{2}  = 49

David had the correct values in each of the parentheses while John had the correct value on the right side of the equation.

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Write the ratio in simplest form in both fractions and in decimal form.
ValentinkaMS [17]

Answer:

Step-by-step explanation:

3 : 12

Both have table of 3 in common so

1 : 4 or 1/4

4 : 64

Both have table of 4 in common

1 : 16 or 1/16

3 0
3 years ago
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I need help with my algebra 2. I also want to know how to solve this.
Lisa [10]

Add 1 to both sides:

\sqrt{x+3} = x+1

In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

x+1 \geq 0 \iff x \geq -1

Under this assumption, we square both sides and we have

x+3 = (x+1)^2 \iff x+3 = x^2+2x+1 \iff x^2+x-2 = 0

The solutions to this equation are

x = -2,\ x=1

But since we can only accept solutions greater than -1, we discard x=-2 and accept x=1.

In fact, we have

x=-2 \implies \sqrt{-2+3}-1=0\neq -2

and

x=1 \implies \sqrt{4}-1=1

which is the only solution.

4 0
3 years ago
Round 3.44570830811 to the nearest hundred-thousandth,
Alika [10]

Answer:

3.44571

Step-by-step explanation:

look at the number to the right of the decimal. if the number is higher than or is 5 round the number up, but if the number is less than 5 it will stay the same.

4 0
3 years ago
Solve for y -5y+8=-3y+10 what is the answer
masha68 [24]
-5y + 8 = -3y + 10
We need to get y on one side.
Add 3y to both sides.
-2y + 8 = 10
We need to get 2y by itself.
Subtract 8 from both sides.
-2y = 2
Divide both sides by -2 to solve for y.
y = -1

I hope this helps!
8 0
3 years ago
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Solve the equation by Completing the Square<br> x2 – 10x + 13 = 0
user100 [1]

Answer:

x=5+\sqrt{12}

or

x=5-\sqrt{12}

Step-by-step explanation:

x^2-10x+13=0

x^2-10x=-13

x^2-10x+(\frac{10}{2})^2 =-13+(\frac{10}{2})^2

x^2-10x+(5)^2=-13+(5)^2

x^2-10x+25=-13+25\\x^2-10x+25=12

Factor.

(x-5)^2=12

Extract the square root.

x-5=\frac{+}{} \sqrt{12}

Add 5

x=5+\sqrt{12}

or

x=5-\sqrt{12}

4 0
3 years ago
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