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nignag [31]
3 years ago
14

Casey picks a bead at random from a box containing 4 red, 36 green, and 10 white beads. What is the probability that she picks 1

red bead, 1 green bead, then 1 white bead, without replacing any of the beads?
Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0
3 red 35 green 95 white
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Are y = 1/4 -2 and y = 1/4 + 2 parallel?
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yes because the slope is equal. so these two lines are parallel.

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What is the degree of the monomial 9xy³z⁷
xxMikexx [17]

Answer:

the degree of the monomial is 11

Step-by-step explanation:

x = 1

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5 0
3 years ago
A clothing manufacturer makes 1,500 pairs of jeans. They ship their jeans to stores in packages of 36. How many full packages wi
Crazy boy [7]

Answer:

a) How many full packages will be used to ship the jeans?

41 packages

b) How many jeans are left over?

24 Jeans

Step-by-step explanation:

We are told that a manufacturer: made 1500 Jeans and is shipping them in packages of 36.

Hence, the number of packages of 36 he can send out to stores is calculated as:

1500÷ 36

= 41.666666667

In whole number packages = 41 packages

Hence, 41 full packages would be used to ship the jeans.

The number of Jeans left behind is

1500 - (41 × 36)

= 1500 - 1476

= 24 Jeans

4 0
2 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
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