288. 4 times 3 is 12. Multiply that with 24 and thats your answer.
For f(x) = cos(x) we have:
- midline = 0
- amplitude = 1
- period = 2π
- graph = bottom graph on the second image.
<h3>
What are the midline, amplitude, period, and graph of the function f(x)=cos(x)?</h3>
For a general cosine function, we have:
f(x) = A*cos(kx + p) + M
Where:
- A is the amplitude.
- k is the frequency.
- p is the phase.
- M is the midline.
For the function:
f(x) = cos(x).
We can see that:
A = 1, M = 0, k = 1, p = 0.
So, the amplitude is equal to 1, and the midline is equal to zero.
Now we also need to get the period. By definition of the trigonometric functions sin(x) and cos(x), we know that the period of the two is equal to 2π.
Finally, we need to identify the graph of cos(x).
Notice that:
f(0) = cos(0) = 1.
So the graph of f(x) = cos(x) is the graph with an y-intercept equal to 1. Which is the bottom graph on the second image.
If you want to learn more about cosine functions:
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Answer:
Step-by-step explanation:
Chungus
Answer:
There were 40 2-point questions and 9 3-point questions.
Step-by-step explanation:
To solve this situation, write two equations. One for the number of questions and one for the number of points.
Let x be the number of 2 point questions.
Let y be the number of 5 point questions.
x + y = 49
Now since x are each worth 2 points, the total points is 2x.
And since y are each worth 5 points, the total points is 5y.
So 2x + 5y = 125. Substitute one of the equations into the other to solve for the variables.
x + y = 49 becomes x = 49 - y. Substitute it.
2(49-y) + 5y = 125
98 - 2y + 5y = 125
98 + 3y = 125
3y = 27
y = 9
Substitute y = 9 back into the equation x = 49 - y to find x.
x = 49 - 9
x = 40
