Question

Claim: Most adults would ease all of their personal information online if they could. A software firm survey of 609 randomly selected adults showed that 55% of
would erase all of their personal information online if they could find the value of the test statistic

The value of the test statisticis

(Round to two decimal places as needed.)

Answer 1

Answer:

2.480 is test statistic

Step-by-step explanation:

Given that the claim is most adults would ease all of their personal information online if they could.

$H_0: p = 0.50\\H_a: p >0.50$

(right tailed test)

p difference = 0.05

Std error=

$\sqrt{pq/n} =\sqrt{0.5*0.5/609}$

0.0202

p difference / std error

Test statistic = p difference / std error

= $\frac{0.05}{0.0202} \\=2.480$