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3 years ago

What is the median of this set of data? 100, 102, 103, 106, 109 100 103 106 109

Mathematics

1 answer:

Strike441 [17]3 years ago

5 0

Answer:

103 is the median.

Step-by-step explanation:

To find the median, you need to put the numbers in order.

100, 100, 102, 103, 103, 106, 106, 109, 109

The median is the number in the middle. After you place them in order, find the number that is in the middle and that will be the median.

Feel free to let me know if you need more help. :)

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A repeated-measures study comparing two treatments with n = 4 participants produces md = 2 and ss = 75 for the difference scores

valentinak56 [21]

The estimated standard error for the sample mean difference is 2.5 .

According to the question

A repeated-measures study comparing two treatments

n = 4

MD(mean difference) = 2

SS (sum of square) = 75

Now,

error for the sample

Formula for standard error

$S^{2} = \frac{SS}{n-1}$

by substituting the value

$S^{2} = \frac{75}{4-1}$

$S^{2} = \frac{75}{3}$

S² = 25

S = 5 (s is never negative)

Standard error of the estimate for the sample mean difference

The standard error of the estimate is the estimation of the accuracy of any predictions.

The formula for standard error of the mean difference

standard error of the mean difference = $\frac{standard\\\ error}{\sqrt{n} }$

standard error of the mean difference = $\frac{5}{\sqrt{4} }$

standard error of the mean difference = 2.5

Hence, the estimated standard error for the sample mean difference is 2.5 .

To know more about estimated standard error here:

brainly.com/question/14524236

#SPJ4

5 0

1 year ago

Question 1: find the volume of a cube whose total surface area is 486cm^2

lapo4ka [179]

<h3>The volume of cube is 729 cubic centimeter</h3>

Solution:

The surface area of cube is given as:

$Surface\ area = 6a^2$

Where, "a" is the length of side of cube

Given that, surface area = 486 square centimeter

$486 = 6a^2\\\\a^2 = \frac{486}{6}\\\\a^2 = 81\\\\a = 9$

Find the volume of cube:

$volume\ of\ cube = a^3\\\\volume\ of\ cube = 9^3\\\\volume\ of\ cube = 9 \times 9 \times 9\\\\volume\ of\ cube = 729$

Thus volume of cube is 729 cubic centimeter

8 0

3 years ago

A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po

igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b) Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c) $z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation

$X_{1}=170$ represent the number of people with the characteristic 1

$X_{2}=110$ represent the number of people with the characteristic 2

$n_{1}=200$ sample 1 selected

$n_{2}=150$ sample 2 selected

$p_{1}=\frac{170}{200}=0.85$ represent the proportion estimated for the sample 1

$p_{2}=\frac{110}{150}=0.733$ represent the proportion estimated for the sample 2

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

a.State the decision rule.

For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c. Compute the value of the test statistic.

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0

3 years ago

When finding the length of the hypotenuse of a right triangle why might you approximate the answer?

sammy [17]

Answer:

Because the hypotenuse might not be a perfect square

Step-by-step explanation:

8 0

3 years ago

Fill in the table using this function rule

tigry1 [53]

This one isn't too hard, just plug in each value!

x = -1
y = -4(-1) + 3
y = 7

x = 0
y = -4(0) + 3
y = 3

x = 1
y = -4(1) + 3
y = -1

x = 2
y = -4(2) + 3
y = -5

8 0

3 years ago

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