No, 0.7 is greater than 0.09
0.70 > 0.09
hope this helps
Given:
Total number of friends = 5
Total cost of all five meals = $51.94
Sales tax = 6%
To find:
The cost of one meal before tax was added.
Solution:
Let x be the cost of all five meals before tax.
Then, Amount of tax = 6% of x
According to he question,
![x+\dfrac{6}{100}x=51.94](https://tex.z-dn.net/?f=x%2B%5Cdfrac%7B6%7D%7B100%7Dx%3D51.94)
![x+0.06x=51.94](https://tex.z-dn.net/?f=x%2B0.06x%3D51.94)
![1.06x=51.94](https://tex.z-dn.net/?f=1.06x%3D51.94)
Divide both sides by 51.94.
![x=\dfrac{51.94}{1.06}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B51.94%7D%7B1.06%7D)
![x=49](https://tex.z-dn.net/?f=x%3D49)
So, the cost of all five meals before tax is $49.
Divide this cost by 5 to get the cost of one meal before tax was added.
![\dfrac{49}{5}=9.8](https://tex.z-dn.net/?f=%5Cdfrac%7B49%7D%7B5%7D%3D9.8)
Therefore, the cost of one meal before tax was added, is $9.8.
Answer:
![f(x) = -2x^2 + 7x + 9](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-2x%5E2%20%2B%207x%20%2B%209)
Step-by-step explanation:
![f(x) = ax^2 + bx + c\\f(0) = 9 => c = 9;\\f(2) = 15 = 4a + 2b + 9 2a + b = 3\\f(3) = 9a + 3b + 9 = 12 3a + b = 1\\Subtract the second equation from the first:\\-a = 2 => a = -2; b = 7; c = 9\\f(x) = -2x^2 + 7x + 9](https://tex.z-dn.net/?f=f%28x%29%20%3D%20ax%5E2%20%2B%20bx%20%2B%20c%5C%5Cf%280%29%20%3D%209%20%3D%3E%20c%20%3D%209%3B%5C%5Cf%282%29%20%3D%2015%20%3D%204a%20%2B%202b%20%2B%209%20%3C%3D%3E%202a%20%2B%20b%20%20%3D%203%5C%5Cf%283%29%20%3D%209a%20%2B%203b%20%2B%209%20%3D%2012%20%3C%3D%3E%203a%20%2B%20b%20%3D%201%5C%5CSubtract%20the%20second%20equation%20from%20the%20first%3A%5C%5C-a%20%3D%202%20%3D%3E%20a%20%3D%20-2%3B%20b%20%3D%207%3B%20c%20%3D%209%5C%5Cf%28x%29%20%3D%20-2x%5E2%20%2B%207x%20%2B%209)
Answer:
Answer is 0.64
Step-by-step explanation:
Given that pdf of x is
![f(x)={k(x−2),for 2≤x](https://tex.z-dn.net/?f=f%28x%29%3D%7Bk%28x%E2%88%922%29%2Cfor%202%E2%89%A4x%3C7%5C%5C%20f%28x%29%3D%7Bk%2812%E2%88%92x%29%2Cfor%207%E2%89%A4x%3C12)
Since total probability is 1 we can use this to find k.
![\int\limits^7_2 {k(x-2)} \, dx +\int\limits^12_7 {k(12-x)} \, dx \\=k\frac{(x-2)^2}{2} -k\frac{(12-x)^2}{2} \\=\frac{k}{2} [(7-2)^2-(2-2)^2-(12-12)^2+(7-12)^2]\\=\frac{k}{2}[25+25]=1\\k =\frac{1}{25}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E7_2%20%7Bk%28x-2%29%7D%20%5C%2C%20dx%20%2B%5Cint%5Climits%5E12_7%20%7Bk%2812-x%29%7D%20%5C%2C%20dx%20%5C%5C%3Dk%5Cfrac%7B%28x-2%29%5E2%7D%7B2%7D%20-k%5Cfrac%7B%2812-x%29%5E2%7D%7B2%7D%20%5C%5C%3D%5Cfrac%7Bk%7D%7B2%7D%20%5B%287-2%29%5E2-%282-2%29%5E2-%2812-12%29%5E2%2B%287-12%29%5E2%5D%5C%5C%3D%5Cfrac%7Bk%7D%7B2%7D%5B25%2B25%5D%3D1%5C%5Ck%20%3D%5Cfrac%7B1%7D%7B25%7D)
the probability that the fire loss is between 5 and 9=![P(5](https://tex.z-dn.net/?f=P%285%3Cx%3C9%29%3D%5Cint%5Climits%5E9_5%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5C%5C%3D%5Cint%5Climits%5E7_5%20%7Bf%28x%29%7D%20%5C%2C%20dx%2B%5Cint%5Climits%5E9_7%20%7Bf%28x%29%7D%20%5C%2C%20dx%5C%5C%3D%288%2B8%29%5Cfrac%7B1%7D%7B25%7D%20%5C%5C%3D0.64)
The slope of the graph is her earnings per hour. The equation for the graph would show a direct variation (proportional relationship) y = mx