Answer: 2 seconds.
Step-by-step explanation:
Given : A ball is thrown upward with an initial velocity of 16 ft/sec from a height of 32 ft above the ground.
The height, in feet, of the ball t sec after it is thrown can be represented by
When ball reaches the ground , s= 0.
Divide both sides by 16 , we get
But time cannot be negative , so t= 2.
Hence , it will take 2 seconds for the ball to reach the ground.