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3 years ago

Solve for the indicated variable. a=f/m for m SHOW ALL WORK

1 answer:

3 0

Ok, a=f/m
What we need to do is isolate the variable, m.
a=f/m
*m *m
a*m=f
m*a=f
/a /a
m=f/a
There's your answer.

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Solve surface area please! Quick it’s due soon

just olya [345]

Answer:

SA = 470 m²

volume = 494 m³

Step-by-step explanation:

Individual areas

Back = 4 x 19 = 76 m²

Top = 5 x 19 = 95 m²

sloped side = 5 x 19 = 95 m²

base = 8 x 19 = 152 m²

end = (4 x 5) + 1/2(3 x 4) = 26 m²

Total SA = 76 + 95 + 95 + 152 + (2 x 26) = 470 m²

Volume

volume = (4 x 5 x 19) + 1/2(3 x 4 x 19) = 494 m³

5 0

2 years ago

What’s the correct answer for this?

grigory [225]

Answer:

The answer is 20

Step-by-step explanation:

Reasoning it is correct because for questions like this the bottom numbers for each shape are 10 and 8 they are very close to each other on the number line there fore since the number is two off you subtract 2 and then two again since it is 2 off to get 21 the closest answer is 20

It is a little confusing but since it is two places off you subtract two twice

8 0

3 years ago

The perpendicular bisector of the line segment connecting the points (-3,8) and (-5,4) has an equation of the form y = mx + b. F

omeli [17]

Answer:

Step-by-step explanation:

find the slope

$\frac{4-8}{-5-(-3)} =\frac{-4}{-2} \\\\slope=2\\y=mx+b\\y=2x+b\\$

take a coordinate to fill in

$(-5,4)\\y=-5\\x=4\\-5=2(4)+b\\-5=8+b-8 -8\\-13=b\\$

this means that the equation is y=2x-13

and if you add m and b

you get :-11

I HOPE THIS HELPS

8 0

3 years ago

Read 2 more answers

Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the

alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

There are 100 students
65 are members of a mathematics club
40 are members of a physics club
10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

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5 0

3 years ago

What the cube root between 100 and 600

N76 [4]

343 is between 100 and 600 and can be cube rooted to 7.

5 0

3 years ago