Which description best compares the graph of y-3=-2(×+4)andy=-2×_5

1 answer:

4 0

Rewrite the first function so that the two functions are in standard form:

y - 3 = -2x - 8 => y = 3 - 2x - 8 => y = -2x - 5

and

y= -2x - 5

We can now see immediately that these two functions have the same slope (-2) and same y-intercept (providing that you meant "y = -2x - 5).

The graphs of these 2 functions are identical.

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20 equals 5 times negative 3 plus x

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Answer:

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Y=(2x-3)^5(2-x^4)^3 differentiate the function please

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$\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
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\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
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\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)$