All categories

3 years ago

The line graph shows the number of video rental stores for the years 2005 through 2012.

Mathematics

1 answer:

yawa3891 [41]3 years ago

3 0

Answer:

do you have a picture of the line graph ?

Answer is 4,000

Step-by-step explanation:

You might be interested in

Please help me!!!!! :)

lora16 [44]

6 / (x + 6) = 10/15

10(x+6) = 90

10x + 60 = 90

10x = 30

x = 3

7 0

3 years ago

At one time the aircraft is 150 m above the surface, the submarine is 25 m below the surface, and the underwater robotic vehicle

EastWind [94]

Answer:

$175$ meter is difference in height between the submarine and the aircraft

Step-by-step explanation:

The height of aircraft above the surface $= 150$ meter

Depth at which the submarine lies below the surface $= 25$ meter

Depth at which the underwater robotic vehicle below the surface $= 186$ meter

Difference in height between the submarine and aircraft is equal to

$25 +150 = 175$ meter

4 0

3 years ago

If the argument of a complex number in polar form is 3pi/2, then it lies on the _____.

IRISSAK [1]

Y axis, between quadrant III and quadrant IV

5 0

2 years ago

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per

ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that $\mu = 2$

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

We want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707$

$P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804$

$P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902$

$P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176$

1.76% probability that in one hour more than 5 clients arrive

8 0

3 years ago

Read 2 more answers

Help!! PLEASE ANSWER ASAP. Please provide why the statement is wrong and give an example!! Math

Vikki [24]

1. false because the GCF of 101 and 102 is 1 whereas the GCF of 33 and 99 is 33.

2. idk

3. false because the GCF of 1 and 2 is 1

3 0

3 years ago