Probably A I am not really sure I am trying sorry if it is wrong
2.0e-6
Is the answer to your question
I will create a set of arbitrary constants (x1,y1) (x2,y2)
slope = y2-y1/x2-x1
y = (y2-y1/x2-x1)x + b
y2 = (y2-y1/x2-x1)x2 + b
b = y2 - (y2-y1/x2-x1)x2
y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]
Choose any points and just
Plug the values and you have a linear function.
NOT SURE IF THAT'S WHAT THE QUESTION WANTS.
It'd be clearer if you'd write: "How many tenths are there in 2 3/5?"
2 3/5 13/5
---------- = ---------- = 26
(1`/10) 1/10
There are 26 tenths in 2 3/5.
