Annabelle is indeed a true story making it fiction
Answer:
1. Check where the file originates from, and if it is a trusted source or his own document, click Enable Content.
2. photo Album feature
3. Outer Join
Explanation:
Answer:
see the code snippet below writing in Kotlin Language
Explanation:
fun main(args: Array<String>) {
sumOfNumbers()
}
fun sumOfNumbers(): Int{
var firstNum:Int
var secondNum:Int
println("Enter the value of first +ve Number")
firstNum= Integer.valueOf(readLine())
println("Enter the value of second +ve Number")
secondNum= Integer.valueOf(readLine())
var sum:Int= firstNum+secondNum
println("The sum of $firstNum and $secondNum is $sum")
return sum
}
Answer:
Possessed objects
Explanation:
Objects that are carried around by users to identify themselves with and to allow them access into computer systems are called possessed objects. Examples of such objects are;
i. smart cards
ii. driver's license
iii. id cards
iv. smart keys
v. smart watches.
Possessed objects are not the only way to allow authentication. Other methods are through memorized information (such as passwords, PINs) and through biometric devices (such as face recognition and voice recognition devices).
Answer:
The description for the given question is described in the explanation section below.
Explanation:
Anyway, after getting acknowledgment from B, C and D will A immediately send a package here. So that we can establish a procedure whereby A must wait until all three acknowledgments are provided.
Start waiting for the specified scenario or situation:
⇒ For sender (sender is A here):
Keep the following steps repeated before all packets are shipped out.
- Step 1 : Place in the broadcast network a fresh packet and configure the wait bit= 1 and the ack bits= 000 and begin the timer (t=0). While bit allows while for the sender(A) to deliver the next packet. Ack parts will hold the earned acknowledgments until now. When first bit= 1 then ack obtained from B, if second bit= 1 then ack obtained from B and instead ack collected from D if the last bit= 1.
- Step 2 : Once sender(A) receives a new acknowledgment, change the ack bits through generating the resulting bit= 1.
- Step 3 : Test if bits of the ack = 111 otherwise render a bit of wait = 0. Go so far as to step 1 and proceed to step 2.
- Step 4 : Whether A has been waiting for t= t0 time and therefore not gotten at least one ack, then place a certain packet on the channel and make t=0, ack bits= 000 and start preparing bit= 1. Then move forward with step 2.
⇒ For receiver (receiver are B, C and C here):
- Step 1 : Wait for another package.
- Step 2 : On delivery of the new document, send ack to the provider and begin countdown t = 0.
- Step 3 : When no latest packet arrives in t= t0 time then give the existing packet acknowledgment again. As it indicates the channel ack may be missing.
- Step 4 : Taking a move to 1.
