Answer:
The cell interior would experience higher than normal Na+ concentrations and lower than normal K+ concentrations.
Explanation:
Na+/K+ ATPase exists in two forms: Its phosphorylated form has a high affinity for K+ and low affinity for Na+. ATP hydrolysis and phosphorylation of the Na+/K+ pump favor the release of Na+ outside the cell and binding of K+ ions from the outside of the cell. Dephosphorylation of the pump increases its affinity for Na+ and reduces that for K+ ions resulting in the release of K+ ions inside the cells and binding to the Na+ from the cells.
The presence of ATP analog would not allow the pump to obtain its phosphorylated form. Therefore, Na+ ions would not be released outside the cells. This would increase the Na+ concentration inside the cell above the normal. Similarly, the pump would not be able to pick the K+ from the outside of the cell resulting in reduced cellular K+ concentration below the normal range.
Answer:
Genotypic ratio = 16 WwDd: 0
Phenotypic ratio = 16 white, disk shaped fruit : 0 yellow, sphere shaped fruit
Explanation:
This question involves two different genes coding for fruit color and fruit shape respectively. The allele for white fruit color (W) is dominant over yellow fruit color (w) and disk shaped fruit (D) is dominant over sphere-shaped fruit (d).
According to this question, If a squash plant pure-breeding for white, disk shaped fruit (WWDD) is crossed with a plant pure breeding for yellow, sphere shaped fruit (wwdd), the following gametes will be produced by each GAMETE:
WWDD - WD, WD, WD, WD
wwdd - wd, wd, wd, wd
Using these gametes in a punnet square, all of the offsprings will have genotype WwDd, which is phenotypically white and disk shaped fruit.
The genotypic ratio is 4 WwDd: 0
The phenotypic ratio is 16 white, disk shaped fruit : 0 yellow, sphere shaped fruit.
The ones about enzymes are chemical digestion and the ones about chewing are mechanical digestion.
Answer:
Can you add the answers please and thank you but i say b
Explanation: