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3 years ago

7

Is a vertical line a function

1 answer:

ohaa [14]3 years ago

7 0

Answer:

No

Step-by-step explanation:

The definition of a function is that for each independent variable there is one dependent variable, and a vertical line has many y-points for one x-point, so no.

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2 years ago

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Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

defon

Answer: 84

<u>Step-by-step explanation:</u>

Set up a proportion as follows: $\dfrac{\text{students that practice everyday}}{\text{total students}}$

$\dfrac{7}{12}=\dfrac{x}{144}$

Cross multiply: 12x = 7 × 144

Divide by 12: x = 7 × 12

Simplify: x = 84

6 0

3 years ago