Answer:
I think it should be the 1st one
Step-by-step explanation:
sorry if it is wrong hope it helps
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:
64
Step-by-step explanation:
the red height is 48 by pythagorean, and by 3:4:5 similarity x=64.
Answer:
y = -|x|+2
Step-by-step explanation:
The graph represents y = |x| where the given graph opens upside down so it's negative and +2 translation towards the top
Answered by GAUTHMATH
