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Nimfa-mama [501]
3 years ago
14

Solve by substitution ANSWER NOW

Mathematics
1 answer:
Maslowich3 years ago
5 0
Y = -5x + 9
y = 5x + 7

5x + 7 = -5x + 9
5x + 5x = 9 - 7
10x = 2
x = 2/10 reduces to 1/5

y = 5x + 7
y = 5(1/5) + 7
y = 1 + 7
y = 8

solution is (1/5,8)
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Given:

7 relations are given.

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The relation which is not a function.

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A relation is called function if there exist unique output for each input.

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{(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}, it is a function.

{(1, 3), (1, 7), (5, 11), (5, 15), (9, 19)}, it is not a function because there exist two y-values y=3 and y=7 at x=1.

{(−2, 4), (−1, 1), (0, 0), (1, 1), (2, 4)}, it is a function.

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{(6, 3), (4, 1), (2, 1), (0,−1), (−2,−3)}, it is a function.

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Making use of the above formula for distance, we have:

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