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Mkey [24]
3 years ago
10

When Mary is late coming home from work, John decides that it's because she has lost interest in their relationship. This situat

ion illustrates the _______ effect.
a. framing
B. anchoring
C. 20-20 hindsight
D. context perception
Advanced Placement (AP)
2 answers:
nata0808 [166]3 years ago
5 0
<span>When Mary is late coming home from work, John decides that it's because she has lost interest in their relationship. This situation illustrates the Framing effect.</span>
Sergeeva-Olga [200]3 years ago
4 0

From the situation described in the question, John seems to have fallen prey to the (A) framing effect in seeing his relationship with Mary.

Framing effect is defined as a<em> cognitive error that a person experiences, where an individual is likely to decide on something based on how they are presented</em>. If it is presented in a negative way, the individual will more likely take risk, but if it is presented in a positive way, the individual will less likely to take risk.

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The velocity of circulation is 4 and the quantity of money is $3 billion.
musickatia [10]

The GDP is $12 billion.

<h3>What is Velocity of circulation in Economics?</h3>

In Economics, Velocity of circulation refers to the circulation of the amount of the money during a given period of the time. The calculation of the velocity of circulation is done by dividing GDP by the country's total money supply.

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3 0
2 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

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