The answer is ASA.
Given that ∠A = ∠O, ∠W = ∠N, SW = TN, this shows that the two angles (∠A and ∠W) and the included side SW of the first triangle are equal to the two angles (∠O and ∠N) and the included side TN of the second triangle. This means that third angles ∠S and ∠T are also equal. Therefore, the two triangles ΔWAS and ΔNOT are congruent based from the ASA Postulate.
When x is 0 y would be -7 and when x=-1 y=-16
Add all the numbers which gives you
102
102 divided by 4 is 25.5
Mean=25.5
Median is 26.5
6y x (11k+12) Hope this helps!
Answer:
2,4,8,11,22, or 44
Step-by-step explanation:
To figure out how many rings would be in each full row with no leftovers, we need to find all the factors of 88 (outside of 1 and 8) which are 2,4,8,11,22, and 44. Since the question does not give any more information on how big the rows need to be, I can't narrow this down any further, however if I had to choose I would say rows of 8 by 11 would be the best.
Hope this helps! :)
