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3 years ago

13

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Find the solution s

et. The solution set for -p2 − 11p = 0 is { }. (Separate the solutions with a comma.)

1 answer:

irina [24]3 years ago

7 0

Answer:

34.55/6.28=0

Step-by-step explanation:

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9x+16<br> 3<br> <7<br> solve each inequality

Crazy boy [7]

Step-by-step explanation:

9+16×+3

28×<7

35x it's answer can I help

8 0

3 years ago

A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju

weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

$V_0 = 12 m/s$

$\theta = 20^0$

$g=9.8 m/s^2$

At maximum height:

$V_y = 0$

Components of initial velocity:

$V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s$

$V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s$

To find time to reach maximum height:

$V_y = V_0y -gt$

Plugging in the known values:

0 = 4.10 - 9.8t

$t = \frac{-4.10}{-9.8}$

$t = 0.418 s$

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

$x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m$

8 0

3 years ago

Copy the table below onto your paper. Complete it then write an equation that relates x and y.

IRISSAK [1]

The equation is y = x - 3. just subtract 3 to get all of the blank spots.

5 0

3 years ago

A rectangular sandbox has an area of 55 square feet. find the length and width of the box if the length is one more than twice t

Dmitrij [34]

Answer:

The length is 5

The width is 11

Step-by-step explanation:

11 is more than two times bigger than 5

(っ◔◡◔)っ ♥ Hope It Helps ♥

4 0

3 years ago

Find the tenth term in each sequence. -1,2/3,7/3,4,17/3

Luba_88 [7]

It'a an arithmetic sequence:

$a_1=-1\\\\a_2=-1+\dfrac{5}{3}=-\dfrac{3}{3}+\dfrac{5}{3}=\dfrac{2}{3}\\\\a_3=\dfrac{2}{3}+\dfrac{5}{3}=\dfrac{7}{3}\\\\a_4=\dfrac{7}{3}+\dfrac{5}{3}=\dfrac{12}{3}=4\\\\a_5=4+\dfrac{5}{3}=\dfrac{12}{3}+\dfrac{5}{3}=\dfrac{17}{3}\\\vdots\\\\\text{The general formula for nth term of an arithmetic sequence}\\\\a_n=a_1+(n-1)d\\\\\text{We have}\ a_1=-1\ \text{and}\ d=\dfrac{5}{3}.\\\\\text{Substitute}\\\\a_n=-1+(n-1)\left(\dfrac{5}{3}\right)=-1+\dfrac{5}{3}n-\dfrac{5}{3}=\dfrac{5}{3}n-\dfrac{3}{3}-\dfrac{5}{3}$

$\boxed{a_n=\dfrac{5}{3}n-\dfrac{8}{3}}$

5 0

3 years ago