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Leviafan [203]
3 years ago
13

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Find the solution s

et. The solution set for -p2 − 11p = 0 is { }. (Separate the solutions with a comma.)
Mathematics
1 answer:
irina [24]3 years ago
7 0

Answer:

34.55/6.28=0

Step-by-step explanation:

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Please answer this question now
Alex787 [66]

Answer:

541.7 (m2)

Step-by-step explanation:

Applying the sine theorem:

WV/sin(X) = XV/sin(W)

=> WV = XV*sin(X)/sin(W) = 37*sin(50)/sin(63) = 31.81

Angle V = 180 - X - W = 180 - 50 - 63 = 67

Denote WH is a height of the triangle VWX, H lies on XV

=> WH = WV*sin(V) = 31.81*sin(67) =  29.28

=> Area of triangle VWX is calculated by:

S = side*height/2 = XV*WH/2 = 37*29.28/2 = 541.7 (m2)

8 0
3 years ago
You get a 3% commission on all sales. This month, you made a sale of $45,050 and
shtirl [24]

Answer:

$1,555.06

Step-by-step explanation:

8 0
3 years ago
F(x) = x^2 -7x +14, g(x) = 4x -9 <br><br> Find (g ° f)(x)
adelina 88 [10]

Answer:

Set up the composite result function.

g(F(x)) Evaluate g(x2−7x+14)

by substituting in the value of F into g.

g(x2−7x+14)=4(x2−7x+14)−9

Simplify each term.

g(x2−7x+14)=4x2−28x+56−9

Subtract 9 from 56.

g(x2−7x+14)=4x2−28x+47

Step-by-step explanation:

5 0
3 years ago
2(4x - 7)<br> What’s the answer
natima [27]

Answer:

8x - 14

Step-by-step explanation:

1. expand by distributing terms.

2 \times 4x + 2 \times -  7

2. Simplify 2 × 4x to 8x.

8x + 2 \times  - 7

3. Simplify 2 × -7 to -14.

8x - 14

Therefor, the answer is, 8x - 14.

3 0
3 years ago
Please help me! Immediate Urgent help please!
KATRIN_1 [288]

Answer:

  • a = 144
  • b = 67

Step-by-step explanation:

When a transversal crosses parallel lines, the interior same-side angles are supplementary. That means ...

  a° and 36° are supplementary, so

  a = 180 - 36 = 144

and

  b° and 113° are supplementary, so

  b = 180 -113 = 67

_____

The bases of this trapezoid are parallel, as indicated by the right-pointing arrow on each one. The left- and right-ends of the trapezoid are lines between the parallel bases that meet the requirement for the marked angles next to each one to be supplementary.

6 0
3 years ago
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