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Licemer1 [7]
4 years ago
5

Which situation can be represented by this inequality? 50−3.50x>100−6x Select one: A. Daniel has a $50 Dunkin Donuts™ gift ca

rd and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have less money on his gift card than David? B. Daniel has a $50 Dunkin Donuts™ gift card and spends $6 a day. David has a $100 gift card and spends $3.50 a day. What is x, the number of days that need to pass for Daniel to have more money on his gift card than David? C.Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have more money on his gift card than David? D. Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have the same amount of money on his gift card as David?
Mathematics
1 answer:
VARVARA [1.3K]4 years ago
6 0

Answer:

Option C is correct

Step-by-step explanation:

Given: inequality is 50-3.50x>100-6x

To find: situation that can be represented by the given inequality

Solution:

Cost of Dunkin Donuts gift card with Daniel = $50

Amount spent by Daniel per day = $3.50

Cost of Dunkin Donuts gift card with David = $100

Amount spent by David per day = $6

Amount left with Daniel after x days = \$(50-3.50x)

Amount left with David after x days = \$(100-6x)

According to question,

Amount left with Daniel after x days > Amount left with David after x days

50-3.50x>100-6x

So, he inequality that satisfies the situation is 50-3.50x>100-6x

Option C is correct

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Answer:


Step-by-step explanation:

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{4x + 2y  =64} / 2    divide the equation by 2

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Step Two

subtract (1) from (3)

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Check

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64 = 64

The checks out to be the right answer.

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3 years ago
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