D= Density
m= mass
V= Volume
D=m÷V
= 8÷32
D= 1/4
Sum of the numbers in the set: 42+37+32+29+20 =160
Current mean: 160/5 = 32
Median = the valvue of the middle = 32.
New mean: 32+10= 42.
Sum of numbers in the new set = 42*8 = 336
Difference: 336 - 160 = 176
I want to include 32, so that the new median stays in 32.
So the other two numbers must add 176 - 32 = 144
I will use a smaller number than 32 and the other greater (again in order to keep the same median.
I will choose 28 and 144 - 28 = 116.
So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}
Checking:
Sum of the terms: 116+42+37+32+32+29+28+20 = 336
Mean = 336 / 8 = 42, which is 10 more than the original mean.
And the new median is (32+32)/2 = 32. The same of the original set.
The kite is 1500 feet above the ground
To solve for n:
n/3+5=7
Subtract 5 from both sides.
n/3=2
Multiply both sides by 3.
n=6
Hope this helps! :)
Answer:
Derrick shaded more
Step-by-step explanation:
I didn't know what you want me to answer but he has more.
