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RSB [31]
3 years ago
14

8x + 5y = -77 3x + y = -14

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0
The answer is -14. Duhhhh
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Given the arc length of a circle is 127π centimeters and the subtended angle is 60˚. Find the Circumference of the circle.
Mumz [18]

The circumference of the circle is 762π cm.

<h3>What is length of arc of a circle?</h3>

The length of arc a circle can is determined with the radius and central angle of the arc.

The radius of the circle is calculated as follows;

L = \pi r \times \frac{ \theta }{180} \\\\&#10;\pi r \theta = 180 L\\\\&#10;\pi  r = \frac{180 L}{\theta}

The circumference of the circle is calculated as follows;

C = 2\pi r\\\\&#10;C = 2(\pi  r)\\\\&#10;C = 2(\frac{180 \ L}{\theta } )\\\\&#10;C = 2(\frac{180 \times 127\pi}{60 } )\\\\&#10;C = 762 \pi \ cm

Learn more about circumference of a circle here: brainly.com/question/9782777

4 0
2 years ago
Which of the following correctly shows the re-grouping for 45 x 12? Group of answer choices 40 x 10; 5 x 10; 40 x 2; 5 x 40
Damm [24]

Answer:

40x10;5x10;40x2;5x2

400+50+80+10

=540

5 0
3 years ago
PLEASE HELP MY GROUP
Hoochie [10]

A=1007.27

B=2895.29

C=≈2714.34

D=111.84

6 0
3 years ago
Read 2 more answers
Saige's spaceship traveled 588 588588 kilometers ( km ) (km)left parenthesis, start text, k, m, end text, right parenthesis in 6
pshichka [43]

Answer:

The first ship has the same speed as Saige's ship while the second and third do not have the same speed.

Step-by-step explanation:

d = Distance traveled by Saige's spaceship = 588 km

t = Time taken = 60 seconds

Speed is given by

s=\dfrac{d}{t}\\\Rightarrow s=\dfrac{588}{60}\\\Rightarrow s=9.8\ \text{km/s}

The other ships

s=\dfrac{441}{45}=9.8\ \text{km/s}

s=\dfrac{215}{25}=8.6\ \text{km/s}

s=\dfrac{649}{110}=5.9\ \text{km/s}

So, the first ship has the same speed as Saige's ship while the second and third do not have the same speed.

8 0
3 years ago
Rewrite the equation in vertex form. then find the vertex of the graph. y=-3x^2-5x+1
amm1812

Answer: y = -3(x + \frac{5}{6})² + \frac{37}{12}, (-\frac{5}{6}, \frac{37}{12})

<u>Step-by-step explanation:</u>

First, you need to complete the square:

y   = -3x² - 5x + 1

<u> -1  </u>   <u>                -1  </u>

y - 1 = -3x² - 5x

y - 1 = -3(x² + \frac{5}{3}x

y - 1 + -3(\frac{25}{36}) = -3(x² + \frac{5}{3}x + \frac{25}{36})

           ↑                     ↓            ↑

                                  \frac{5}{3*2} = (\frac{5}{3*2})^{2}

y - 1 - \frac{25}{12} = -3(x + \frac{5}{6})²

y - \frac{12}{12} - \frac{25}{12} = -3(x + \frac{5}{6})²

y  - \frac{37}{12} = -3(x + \frac{5}{6})²

y = -3(x + \frac{5}{6})² + \frac{37}{12}

Now, it is in the form of y = a(x - h)² + k   <em>where (h, k) is the vertex</em>

Vertex = (-\frac{5}{6}, \frac{37}{12})

8 0
3 years ago
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