Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
Answer: The answer is the first one, angle JLK
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
1 : 2 = 1/2 : 2 = 1/4 : 2 = 1/8 : 2 = 1/16 : 2 = 1/32 : 2= 1/64
75% = 330 gumballs
Find 1%:
1% = 330 ÷ 75 = 4.4 gumballs
Find 100%:
100% = 4.4 x 100 = 440 gumballs.
Answer: 440 gumballs.
Answer:
area = 50.27
circumference = 25.13
Step-by-step explanation:
area
pi x radius²
pi x 4² = 50.27
circumference
pi x diameter = 8 pi
8 pi = 25.13
