Find the sample space for tossing 2 coins. Then find p(exactly one head)
1 answer:
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In ∆ ABC and ∆ADC
AB=AD
AC=AC(common side)
BC=DC
So, ∆ABC and ∆ADC are congruent triangles,
so, m<ABC= m<ADC(corresponding angles of the congruent triangles)
x= 97°
Answer:
b ≈ 101.52
Step-by-step explanation:
Given two sides and the angle between, the Law of Cosines is useful.
b^2 = a^2 +c^2 -2ac·cos(B)
b^2 = 105^2 +9^2 -2·105·9·cos(65°) ≈ 10307.251
b ≈ √10307.251
b ≈ 101.52
