Question

Please answer I’ll rate brainlyest

Answer 1

Answer:

1

Step-by-step explanation:

5C5

= 5! / (5! (5 - 5)!)

= 5! / 5! 0!       (0! =1)

= 1/1

= 1

Answer 2

For this case we have that by definition:

$C (n, r) = \frac {n!} {r! * (n-r)!}$

So:

$C (5,5) = \frac {5!} {5! * (5-5)!}\\C (5,5) = \frac {1} {0!}$

By definition:

$0! = 1$

$C (5,5) = \frac {1} {1} = 1$

Answer:

$C (5,5) = 1$

Option B