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Stels [109]
3 years ago
13

Match the following. 1. the basic building block of all forms of life resolving power 2. the idea of Schleiden and Schwann that

the basic unit of life is the cell and that all living organisms are composed of cells cell 3. theory that states that the basic unit of life is the organism itself, which may be divided into cells for efficiency cell theory 4. the ability to clearly distinguish between two objects organismal theory
Biology
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

1. Cell

2. cell theory

3. Organismal theory

4. resolving power

Explanation:

The cell is the smallest known unit of all living organisms. They are called the building blocks of life. An organism can be unicellular (made up of one cell) or multi-cellular (made up of many cells).

2. Cell theory was formulated and developed  by Schleiden, Schwann, and Virchow. They are considered as the basic principles of biology.

It states:

1. Living organisms are made up of cells.

2. Cells are the basic unit of life.

3. Cells are formed from pre-existing cells.

4. Energy flows inside the cell.

5. DNA is passed on from cell to cell.

6. All cells have the same basic chemical composition.

3. Organismal theory is the intended counter-argument of the cell theory. It was developed by Reichert, Strasberger, Sherrington, and Pavlov. It argues that the basic unit of life is the organism itself, suggesting that an organism came about from a cell that expanded.

4. Resolving power is the ability of an optical instrument like a microscope or a telescope to view objects that are close together as separate, abling the viewer to distinguish the two from each other.

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The kcat for Rubisco is 3 sec-1 How long does it takeone<br> subunit of Rubisco to do one reaction.
bekas [8.4K]

Answer:

A subunit of Rubisco takes approximately 0.33 s to perform one reaction

Explanation:

The kcat it's a kinetic first order constant that related the properties of the enzyme substrate complexes in a mechanisms and represents the overall first order process of the transformation of the substrate-enzyme complex into product.

Also kcat can be seen as the turnover number of an enzyme, representing the maximum number of substrate molecules that the enzyme can transform into product per time unit and per active site.

If the kcat is 3 s^-1, it means Rubisco can catalyse the transformation of 3 substrate molecules per second.

So, the time that takes a single reaction, should be the inverse of kcat.

To see it more clearly, the time needed for a single reaction is the time observed divided by the number of reactions done during that time.

In other words:

3 reactions ----------- 1 s

1 reaction -------------- x

  • x=1 reaction/3 reactions.s^-1 = 1/kcat = 1/3 s ~ 0.33 s

So the time that takes one Rubisco subunit to do one reaction is approximately 0.33 s

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3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
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Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
  • Insolation energy is 800 calories/cm2/day
  • % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

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