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Natali [406]
3 years ago
5

Frequency (y) varies inversely with wavelength (x). Find the frequency (measured in THz ) of blue light if its k value is 175,72

0 and its wavelength is 230 meters. (Round to nearest whole number if necessary)
Mathematics
1 answer:
horsena [70]3 years ago
8 0

We have been that frequency (y) varies inversely with wavelength (x).

We know that two inversely proportional quantities are in form a=\frac{k}{b}, where a is inversely proportional to b and k is constant of variation.

Our required equation would be y=\frac{k}{x}.

To find frequency of blue light, we will substitute k=175,720 and x=230 in our equation as:

y=\frac{175,720}{230}

y=764

Therefore, the frequency of blue light is 764.

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Calculate the future value of $51,123.21, earning interest at a rate of that is compounded daily for 20 years and 2 months (use
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The following is the frequency distribution for the speed of a sample of automobiles traveling on an interstate highway. Speed (
svlad2 [7]

Answer:

Standard Deviation is 18.57 .

Step-by-step explanation:

We are given the frequency distribution for the speed of a sample of automobiles traveling on an interstate highway;

  Speed (mph)     Frequency (f)      X         X*f           X - Xbar        (X-Xbar)^{2}

     50 - 54                    4                52       208         52 - 65 = -13         169

     55 - 59                    3                57        171           57 - 65 = -8           64

     60 - 64                    2                62        124          62 - 65 = -3            9

     65 - 69                    5                67        335          67 - 65 = 2             4

     70 - 74                     2                72        144           72 - 65 = 7            49

     75 - 79               <u>      5       </u>         77     <u>   385    </u>      77 - 65 = 12          144

                                <u> ∑f = 21   </u>              ∑X*<u>f = 1367 </u>            

Mean of the data, Xbar = \frac{\sum Xf}{\sum f}

                                       = \frac{1367}{21} = 65.09 ≈ 65 .        

Now, Standard deviation, s = \sqrt{\frac{\sum f*(X-Xbar)^{2} }{n-1}}

s =  \sqrt{\frac{(4*169)+(3*64)+(2*9)+(5*4)+(2*49)+(5*144)}{6-1} } = \sqrt{\frac{1724}{5} } = 18.57

Therefore, standard deviation is 18.57 .

           

5 0
3 years ago
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