The materials plants need in order to perform photosynthesis are Water and carbon dioxide.
<h3>What is photosynthesis?</h3>
Photosynthesis is a process of converting light energy into chemical energy.
Photosynthesis is performed by chlorophyll-containing plants to produce their food.
The process of photosynthesis is carried out in the presence of sunlight.
It requires water, carbon dioxide, and sunlight.
Thus, the correct option is B, water, and carbon dioxide.
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Non-prokaryotic organisms typically have two life cycle stages: trophozoite and cyst is Protozoa.
<h3>What is Protozoa?</h3>
- Protozoa is a group of single celled, non- prokaryotic organisms.
- These may either be free living or parasitic in nature.
- These are heterotrophs and reproduce asexually by binary fission.
- The Protozoa consists of many unrelated or loosely related organisms.
- They are divided into four major groups: Sarcodina, Flagellates, Ciliates and Sporozoans..
- Some protozoa consist of two phases in their life cycle: proliferative stage (trophozoites) and resting stage (cysts).
- Trophozoites consists of the proliferative stage in which the protozoa divides and reproduces.
- The resting cyst form helps the protozoa to survive harsh environmental conditions like harmful chemicals, extreme temperature and nutrient and water deficiency.
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Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Since it's been crossed with a homozygous wrinkled green, the offspring has a genotype for heterozygous round and yellow. As round and yellow are dominant traits, they're expressed in the phenotype. But when self pollinated in the f2 generation, the recessive ones will show as well
Hope it helps :')
Answer:
In the ecosystem, the tides of the water rise in each figure. In figure 4, there is an increase in land animals present, and a lower amount of aquatic animals present. In the first figure, there are no birds, however there are multiple in the rest of the figures, this is possibly due to migration in the winter or that the ecosystem has drawn birds near. The types of plants change throughout each figure which is most likely to new adaptations such as more water available. The tides most likely rose because of more precipitation.
Explanation:
I hope this helped.
