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saul85 [17]
3 years ago
9

A retailer returned 2700 defective items to the manufacturer and received a credit for the retail price of $0.83 or 834/34 per i

tem less a discount of of the retail price. What was the amount of the credit received by the retailer?
Mathematics
1 answer:
Helga [31]3 years ago
8 0

Answer:

credit gain by retailer is $2257.39

Step-by-step explanation:

Given data:

Retaile price 83 4/3 c or 84.33c

Let Discount rate 6/7

Discount amount = (6/7)% of 84.33 c = 0.7228 C

Net credit received = 84.33c - 0.7228c = 83.607c

Net credit received = 83.607 c

Item required  = 2700

Total discount = 2700 × 83.0607 = 225739.44c

Total discount = $2257.39

credit received by retailer is $2257.39

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Which letter will correspond to the location of the following points when plotted on the number line below?
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Answer:

A, E, B, D, C

Step-by-step explanation:

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3) √40 = 6.3, so it is B

4) √64 = 8, so it is D

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2 years ago
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1406 referee​ calls, with the re
erastova [34]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for men and women players. The population proportions of men and women challenges for calls would be p1 and p2

P1 - P2 = difference in the proportion of men and women challenges for calls.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 416

n1 = 1406

P1 = 416/1406 = 0.3

For new dough,

x2 = 217

n2 = 778

P2 = 217/778 = 0.28

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (416 + 217)/(1406 + 778) = 0.29

1 - pc = 1 - 0.29 = 0.71

z = (P1 - P2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.3 - 0.28)/√(0.29)(0.71)(1/1406 + 1/778) = 0.02/√0.00553857907

z = 0.99

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score to the left of 0.99 is 1 - 0.84 = 0.16

We would double this area to include the area in the left tail of z = - 0.99 Thus

p = 0.16 × 2 = 0.32

Since 0.1 < 0.5, we would accept the null hypothesis.

p value = 0.337

Since 0.05 < 0.32, we would accept the null hypothesis

7 0
3 years ago
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