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Oksi-84 [34.3K]
3 years ago
14

Three fractions between 4/5 and 4/6

Mathematics
1 answer:
Ilya [14]3 years ago
5 0
4/5=24/30 and 4/6=20/30 So three easy fractions between these are 21/30=7/10, 22/30=11/15 and 23/30.
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the distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way.
Sholpan [36]

The distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way. The distance ezra runs can be solve by multiplying 8/10 to the total distance.

X = 0.9(8/10)=0.72 mile

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3 years ago
Which graph represents the function?
Eva8 [605]
The top right graph
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2 years ago
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Please Help! The graph of y=f(x) is shown below. What are all of the real solutions of f(x)=0? (Picture of graph included)
qwelly [4]

Answer:

(7, 0), (-8, 0), (0, 0)

Step-by-step explanation:

y = f(x) = 0

the real solutions are the ones that cross the x-axis because when a point is on the x-axis, its y coordinate will be 0.

=> (7, 0), (-8, 0), (0, 0)

6 0
3 years ago
A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert
andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of ​​the circular sector using the following equation.(c in the second attached image)

A=\frac{R^2}{2} (\alpha -sin\alpha )

\alpha =2arccos(\frac{d}{R})

3. observing the attached images we replace the values ​​in the equations and find the area of ​​the circular sector, remember that you must transform the angle to radians

\alpha =2arccos(\frac{5}{7})=88.83

A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2

4.we calculate the area of ​​the total circle (At), then subtract the area of ​​the circular sector (Ac) to find the area occupied by water (Aw)

At=\frac{\pi }{4} (14ft)^2=153.93ft^2

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of ​​the water over the total area of ​​the tank

\frac{116.36}{153.93} *100=75.6

percentage of the total capacity is 75.6%

3 0
2 years ago
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goldenfox [79]

Answer: $20

Step-by-step explanation:

half of 40 is 20.....

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3 years ago
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