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Marrrta [24]
3 years ago
12

Simplify: (2^2 + 3^4)−^2

Mathematics
2 answers:
blondinia [14]3 years ago
7 0

(2^2 + 3^4)^-2

2^2 =4

3^4 = 81

2^2 + 3^4 = 4+81 = 85

85^-2

1/85^2

1/7225

Lisa [10]3 years ago
5 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (2^2+3^4)^{-2}\implies (4+81)^{-2}\implies 85^{-2}\implies \cfrac{1}{85^2}\implies \cfrac{1}{7225}

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A box with a square and a closed top must have a volume of 125 cubic inches. Find the dimensions of the box that minimize the am
attashe74 [19]
If a box has a square base its volume will be:

V=hb^2  where h is the height...

h=V/b^2  we are told that V=125 so

h=125/b^2  now for the surface area, which consists of the two bases for a total of 2b^2.  It will also have four sides with a total area of 4(bh)=4bh so

A=2b^2+4bh, using h found above in this gives us:

A=2b^2+4b(V/b^2)

A=2b^2+4V/b

A=(2b^3+4V)/b, then taking the derivatives we can find the velocity of the area function.

dA/db=(6b^3-2b^3-4V)/b^2

dA/db=(4b^3-4V)/b^2

dA/db=0 when 4b^3-4V=0

b^3=V

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h=b=5in
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