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Anna11 [10]
3 years ago
7

PLSS IS 9/8 BIGGER THAN 31/32

Mathematics
2 answers:
satela [25.4K]3 years ago
4 0

Answer: yes because the smaller the numbers the bigger they are

Step-by-step explanation:

kirill115 [55]3 years ago
3 0

Hello!

To compare fractions, they have to have the same denominator (the number on the bottom.) As you can clearly see, 9/8 has a denominator of 8 and 31/32 had a denominator of 32. Is 8 and 32 the same number? Of course not. We have to make them the same. But how?

Use the LCM. I don't want to go into much detail here on what that is (if you don't already know what that is) if you don't know what it is, please go ahead and look up how to find the LCM of two numbers. In our case we're comparing fractions so it's actually called the LCD, but it's still the LCM.

So, LCM = Largest Common Multiple. The largest common multiple that 8 and 32 shares is 32! So, what do we do? Well, we keep 31/32 the same because it already has the right denominator. 9/8 on the other hand has to change. 8 * 4 = 32. Know that whatever we do to the denominator, we HAVE to do to the numerator. So, 9 * 4 = 36. Our new fraction is 36/32.

So let's compare our fractions

36/32 and 31/32

When comparing fractions, if they have the same denominator, all you have to do is look at the numerators. 36 is larger than 31, yes? So 36/32 is the bigger fraction! Or should I say, 9/8 is bigger.

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Step-by-step explanation:

range=highest -lowest

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3 years ago
-(5m+1)<br> please help me!!!!!!!!
Art [367]

Answer:

-5m-1

Step-by-step explanation:

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4 0
3 years ago
Answer the following
Amanda [17]

The set A satisfying the given inequality is A = (-\infty, -10].

<h3>What are some properties of an inequality relation? </h3>

Following are some facts which are true for an inequality relation:

  • Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.
  • The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.

\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)

Since y ∈ B, -2 ≤ y ≤ 7. So,

\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\;  y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.

The set {-x | inequality (1) holds ∀ y ∈ B} is [10, \infty) i.e.

10 ≤ -x ≤ \infty.

Multiplying -1 throughout gives

-10 ≥ x ≥ -\infty.

x, thus, lies in the range A = (-\mathbf{\infty}, -10}.

Learn more about the inequality here.

brainly.com/question/17801003

Disclaimer: The question was incomplete. Please find the full content below.

<h3>Question </h3>

Find the set A such that for x ∈ A

\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y

∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.

#SPJ4

4 0
2 years ago
The course for a local triathlon has the shape of a right triangle. The legs of the triangle consist of a 4-mile swim and a 11 m
Annette [7]

Answer:

The biking part of the triathlon is 11.70 miles away.

Step-by-step explanation:

From the right angle Δ ABC

AC^{2} = AB^{2} + BC^{2}

Since AB = 4 mile

& BC = 11 miles

⇒ AC^{2} = 11^{2} + 4^{2}

⇒ AC^{2} = 121 + 16

⇒ AC^{2} = 137

⇒ AC = \sqrt{137}

⇒ AC = 11.70 miles

Thus the biking part of the triathlon is 11.70 miles away.

8 0
4 years ago
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