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viktelen [127]
4 years ago
11

Expression that have an rational product?

Mathematics
1 answer:
Pani-rosa [81]4 years ago
7 0

Step-by-step explanation:

step 1: factor both the numerator and the denominator

step 2: write as on fraction

step 3: simplified the rational expression

step 4: multiply any remaining factors in numerator and or denominator

step 5: factor both the numerator and the denominator

step 6: write as on fraction

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It costs Edgar $2.65 one way to ride the bus to work. He uses the bus to go to and from work fourdays per week. He buys a bottle
Alja [10]

Answer:

$27 per week.

Step-by-step explanation:

Multiply:

$2.65 x 8 (twice per day)= $21.20

$1.45 x 4 (once oer day)=$5.80

Add those together to get $27 per week.

7 0
4 years ago
Solve for y please!!!!!!!!!!!!
sergij07 [2.7K]

Answer:

y=3r-230

Step-by-step explanation:

Subtract the 3r from the first aide to put it along with the 230. Then, we must divide both sides by negative 1 to get y by itself. This gives us y=3r-230.

5 0
3 years ago
Which graph is the solution to |x| > 10?
gtnhenbr [62]

|x| > 10

x < - 10 or x > 10

The plot is open dots on -10 and 10 and shading to the left of -10 and to the right of 10.

Answer is the third choice.

8 0
4 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Marina86 [1]

Answer:

Divergent.

Step-by-step explanation:

We have been given an integral \int\limits^\infty _1 {\frac{1}{x^{0.999}} \, dx. We are asked to determine whether the given integral diverges or converges.

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx

\int _1^{\infty }\:\:\:\frac{1}{x^{0.999}}\:\:\:dx=\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{-0.999+1}}{-0.999+1}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=\frac{x^{0.001}}{0.001}

\int _1^{\infty }\:\:\:x^{-0.999}\:\:\:dx=1000x^{0.001}

Let us compute the boundaries.

1000(\infty)^{0.001}=\infty

1000(1)^{0.001}=1000

Since \infty-1000 is not a finite number, therefore, the given integral diverges.

4 0
3 years ago
Last winter Armand had StartFraction 5 Over 6 EndFraction of a row of stacked logs. At the end of the winter he had StartFractio
irina [24]

Answer:

3/10

Step-by-step explanation:

We have that the Armans last winter had 5/6 of a row of stacked logs and at the end of the winter he had 8/15 of the same row left, therefore:

Ambitious

First we have to do is that the denominator is the same.

in the case of 5/6 it would be 25/30

and for 8/15 it would be 16/30

Now if we can do the subtraction and it would be:

25/30 - 16/30 = 9/30 or what equals 3/10

3/10 was the amount of wood he burned in the winter

6 0
4 years ago
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