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aleksley [76]
3 years ago
8

10) Find four consecutive even integers whose sum is 100. What is the equation used?​

Mathematics
1 answer:
mihalych1998 [28]3 years ago
3 0

Answer:22

Step-by-step explanation:

Let x be the smallest even integer.

Thus, our next numbers are x+2, x+4, and x+6.

Summing them up, we get 4x+12=100. Hence, x=22.

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ser-zykov [4K]

Answer:

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3 0
3 years ago
PLEASE HELP ME NOW!!!!! ILL GIVE BRAINLIEST!!!
natulia [17]

Answer:

its C. 17/10

Bcs 3/2

=1.5

And on the figure shown 1.5 comes in c

<h2>Mark me BRAINLIEST </h2>
8 0
3 years ago
Read 2 more answers
PLEASE HELP! WILL MARK BRAINLIEST!!
ycow [4]

Answer:

18/121

1/4

(not 100% sure)

6 0
4 years ago
How to write and solve 445.76 x 9.634
STALIN [3.7K]

445.76 *  9.634

use your calculator 

answer is   4294.45184
4 0
3 years ago
Could someone please help me:) I am stick and I am not sure what to do ​
Delicious77 [7]

Answer:

Part 5.1.1:

\displaystyle \cos 2A = \frac{7}{8}

Part 5.1.2:

\displaystyle \cos A = \frac{\sqrt{15}}{4}

Step-by-step explanation:

We are given that:

\displaystyle \sin 2A = \frac{\sqrt{15}}{8}

Part 5.1.1

Recall that:

\displaystyle \sin^2 \theta + \cos^2 \theta = 1

Let θ = 2<em>A</em>. Hence:

\displaystyle \sin ^2 2A + \cos ^2 2A = 1

Square the original equation:

\displaystyle \sin^2 2A = \frac{15}{64}

Hence:

\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1

Subtract:

\displaystyle \cos ^2 2A = \frac{49}{64}

Take the square root of both sides:

\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}

Since 0° ≤ 2<em>A</em> ≤ 90°, cos(2<em>A</em>) must be positive. Hence:

\displaystyle \cos 2A = \frac{7}{8}

Part 5.1.2

Recall that:

\displaystyle \begin{aligned}  \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &=   1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}

We can use the third form. Substitute:

\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1

Solve for cosine:

\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}

In conclusion:

\displaystyle \cos A = \frac{\sqrt{15}}{4}

(Note that since 0° ≤ 2<em>A</em> ≤ 90°, 0° ≤ <em>A</em> ≤ 45°. Hence, cos(<em>A</em>) must be positive.)

4 0
3 years ago
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