Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
Answer:
d. all of the statements are correct
Explanation:
Frame Relay is a high-performance WAN protocol that operates at the physical and data link layers of the OSI reference model. i.e Layers 1 and 2 They are designed to cope with bursty traffic. Frame relay is also a form of data networking based on packet switching in which the packets are variable in length and experience packet delays.
Based on the above definition the correct statement is option d as all of the statements define in the other option correctly defines the function of frame relay.
Constructor method
The new operator instantiates a class by allocating memory for a new object of that type. new requires a single argument: a call to a constructor method. Constructor methods are special methods provided by each Java class that are responsible for initializing new objects of that type.
Answer: A #3f107f.
Letter B would produce a lighter blue-purple color rather than a darker shade of purple. Letter C would produce a very light purple color. Letter D would produce a Black color, making it very dark and not in the range of being purple.
Letter A would produce a darker shade of purple. As explained in the way that the RGB color hexadecimal uses, the amount of each respective color is 2 digits for each color Red, Green, Blue respectively. By reducing the amount of each color in the RGB mode, the output will become a darker shade as the RGB mode is an ADDITITIVE type of color mode.
