Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w
if the length is 7in more than the width, then
L=7+w
Now we will substitute 7+w in for L. Here is our new equation:
66=2(7+w) + 2w
Solve for w
66=14+2w+2w
66=14+4w
52=4w
w=13
L=7+13, so L=20
I hooe this is explained well enough
The brainliest answer you are looking for is 48cm2
Answer:4
Step-by-step explanation: Because 4 goes in 3/4 better and more eqvilent to that answer.
No real solutions, because for all real numbers the square of number is greater or equal 0.
