Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
Answer:
The second option.
3x + 6 = 21.
Step-by-step explanation:
3x + 6 = 21.
If x = 5, plug it in.
3 · 5 + 6 = 21
15 + 6 = 21
Hope this helps,
Davinia.
Answer:
(16a + 6b) (2x - 3y)
Step-by-step explanation:
32ax + 12bx - 48ay - 18by
(32ax - 48ay) + (12bx - 18by)
16a(2x - 3y) + 6b(2x - 3y) Factor out in both seperate expressions
(16a + 6b) (2x - 3y) Double factoring
Pretty Sure Its B I had this question Too
I think that the best answer here would be that A = 40 degrees.
