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luda_lava [24]
2 years ago
11

Environmentalists in Florida are against offshore drilling in the Gulf of Mexico MAINLY because the drilling might

Geography
2 answers:
Helen [10]2 years ago
8 0

The correct answer is A) polluted beaches.

Environmentalists in Florida are against offshore drilling in the Gulf of Mexico MAINLY because the drilling might polluted beaches.

The Gulf of Mexico has represented a strategic place for the extraction of oil and gas for the United States. There are millions of dollars invested in this region to continue the exploitation of natural resources. The offshore of Louisiana, Florida, Mississipi, and Alabama are important oil and gas extraction areas that represent a profitable business for oil companies. This offshore drilling has consequences for the environment and many environmentalists in these states had organized demonstrations against these companies.

Finger [1]2 years ago
5 0
The answer is <span>A) polluted beaches. it will ruin the beaches </span>
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Answer : The value of x_6 is \sqrt{7}.

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of x_1.

Using Pythagoras theorem in triangle 1 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

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x_1=\sqrt{(1)^2+(1)^2}

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Now we have to calculate the value of x_2.

Using Pythagoras theorem in triangle 2 :

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(x_2)^2=(1)^2+(\sqrt{2})^2

x_2=\sqrt{(1)^2+(\sqrt{2})^2}

x_2=\sqrt{3}

Now we have to calculate the value of x_3.

Using Pythagoras theorem in triangle 3 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_3)^2=(1)^2+(X_2)^2

(x_3)^2=(1)^2+(\sqrt{3})^2

x_3=\sqrt{(1)^2+(\sqrt{3})^2}

x_3=\sqrt{4}

Now we have to calculate the value of x_4.

Using Pythagoras theorem in triangle 4 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_4)^2=(1)^2+(X_3)^2

(x_4)^2=(1)^2+(\sqrt{4})^2

x_4=\sqrt{(1)^2+(\sqrt{4})^2}

x_4=\sqrt{5}

Now we have to calculate the value of x_5.

Using Pythagoras theorem in triangle 5 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_5)^2=(1)^2+(X_4)^2

(x_5)^2=(1)^2+(\sqrt{5})^2

x_5=\sqrt{(1)^2+(\sqrt{5})^2}

x_5=\sqrt{6}

Now we have to calculate the value of x_6.

Using Pythagoras theorem in triangle 6 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_6)^2=(1)^2+(X_5)^2

(x_6)^2=(1)^2+(\sqrt{6})^2

x_6=\sqrt{(1)^2+(\sqrt{6})^2}

x_6=\sqrt{7}

Therefore, the value of x_6 is \sqrt{7}.

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