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marishachu [46]

3 years ago

11

How do I solve these equations?

1 answer:

zimovet [89]3 years ago

3 0

Can you use a calculator? If yes, then isolate 7) cot 8) tan 2 theta, etc. Then, input the inverse of that trig into the calculator.

Ex. #7 cot theta= -6/5
Then, input arccot (-6/5) (aka inverse cot (-6/5)) into your calculator.

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Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Only the math gods can write this 50 PT proof!

fredd [130]

Answer:

because the 1st corner and the 2nd corner is places in a straight line which the total agle is 180° so since the 1st corner has same angle as the 13th one the 14th is must be have same angle as the 2nd corner. so that the 1st corner + the 14th corner is equal as 180°

3 0

3 years ago

Need the answer ASAP

sergey [27]

the last option is correct

5 0

3 years ago

What's the lcm for 18, 27, 12? I got 648. Am not sure if it is correct. Can you please explain if it is correct or not?

erik [133]

Answer:

Step-by-step explanation:

Put these numbers into their prime factors.

18: 2 * 3 * 3

27: 3 * 3 * 3

12: 2 * 2 * 3

The LCM must have

two 2s

Three 3s

That's it

2*2 * 3 * 3 * 3

LCM = 108

648 might be a multiple of the three, but it's not the smallest one.

108 = 27 * 4

108 = 18 * 6

108 = 12 * 9

6 0

3 years ago

Jeremiah has $10 to spend at the football

Nookie1986 [14]

Answer:

if;

d=0 p=6

d=3 p=4

d=6 p=2

Step-by-step explanation:

just substitute the value into d and use algebra rules to solve!

7 0

3 years ago