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marishachu [46]
3 years ago
11

How do I solve these equations?

Mathematics
1 answer:
zimovet [89]3 years ago
3 0
Can you use a calculator? If yes, then isolate 7) cot 8) tan 2 theta, etc. Then, input the inverse of that trig into the calculator. 

Ex. #7 cot theta= -6/5
Then, input arccot (-6/5) (aka inverse cot (-6/5)) into your calculator.
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20 POINTS MARKING BRAINLEIST JUST BE QUICK
mr Goodwill [35]

Answer:

4f^2 - r^2 + 3r

Step-by-step explanation:

(4f^2 + 6r + 3) - (r^2 + 3r + 3)

Distribute

4f^2 + 6r + 3 - r^2 - 3r - 3

subtract +3 from -3

4f^2 + 6r - r^2 - 3r

combine like terms

4f^2 + 3r - r^2

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3 0
2 years ago
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What is 8-6g+15=19 step by step
taurus [48]
8 -6g + 15 = 19

You want to isolate the terms (separated by +) that doesn't have letters next to it, to the other side.

So, get 8 and 15 to the other side by subtracting both sides. They don't have letters next to them.

-6g =-4

Divide the -6 on both sides to get "g" alone.

g = 4/6

Simplify

g= 2/3



8 0
3 years ago
What does the graph of f(x)=3x^2-2x+1 look like
aleksklad [387]

Answer:

Below.

Step-by-step explanation:

This is a parabola.

As the coefficient of x^2 is positive it will open upwards ( shaped like a 'U').

If we convert to vertex form we can find the line of symmetry  and the coordinates of the vertex:

f(x) = 3x^2 - 2x + 1

f(x) = 3(x^2 - 2/3 x) + 1

f(x) = 3[(x - 1/3)^2 - (1/3)^2] + 1

f(x) = 3(x - 1/3)^2 - 1/3 + 1

f(x) = 3(x - 1/3)^2 + 2/3

So the line of symmetry is  x = 1/3 and

the vertex ( the minimum of the curve) is at (1/3, 2/3).

5 0
3 years ago
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Nata [24]

Answer:

148

Step-by-step explanation:

4 0
3 years ago
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