The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
<h3>Calculation of the total capital invested</h3>
The time the investment lasted= 12 years.
Simple interest = 1579.05 - 800= $779.05
The principal capital= $800
Rate of the both capital invested;
= SI × 100/P ×T
= 779.05 × 100/800 × 12
= 77,905/9600
= 8.11%
To find the amount of money that Phyllis invested at each given rate,
Rate 1 = 4/8.11× 800
= 3200/8.11
= $394.57
Rate 2 = 6/8.11× 800
= 4800/8.11
= $591.86
The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
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A
Step-by-step explanation:the answer is you have 8 quarter and 13 dimes .
Because you have 5 more dimes than quarters which will equal 3 dollars and 30 cents
Using the data for each truck lets calculate,
median for truck 1 - 511.5
median for truck 2 - 650.5
lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively
B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong
C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct
D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong
Answer:
5/6
Step-by-step explanation: