The ratio 20 minutes to 1hour can be written is n the form 1:n find the value of n

Yikes mctugg bought 1/2pound of potato salad . He ate 2/3of it for lunch .How much potato salad was left for an afternoon snack

Anna007 [38]

$\frac{1}{2} - \frac{2}{3}( \frac{1}{2}) = \frac{1}{2} - \frac{2}{6} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6} pound$

5 0

3 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0

3 years ago

Using a table of values, determine the solution to the equation below to the nearest fourth of a unit.

Leto [7]

2x-4=3-x +1
<span>Simplifying 2x + -4 = 3 + -1x + 1
Reorder the terms: -4 + 2x = 3 + -1x + 1
Reorder the terms: -4 + 2x = 3 + 1 + -1x
Combine like terms: 3 + 1 = 4 -4 + 2x = 4 + -1x
Solving -4 + 2x = 4 + -1x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add 'x' to each side of the equation. -4 + 2x + x = 4 + -1x + x
Combine like terms: 2x + x = 3x -4 + 3x = 4 + -1x + x
Combine like terms: -1x + x = 0 -4 + 3x = 4 + 0 -4 + 3x = 4
Add '4' to each side of the equation. -4 + 4 + 3x = 4 + 4
Combine like terms: -4 + 4 = 0 0 + 3x = 4 + 4 3x = 4 + 4
Combine like terms: 4 + 4 = 8 3x = 8
Divide each side by '3'. x = 2.666666667
Simplifying x = 2.666666667</span>

8 0

3 years ago

Read 2 more answers

Find the product <br> (7x^2y^3)(3x^5y^8)

brilliants [131]

Hello!

$\large\boxed{21x^7y^{11}}}$