Answer:
The 95% of confidence intervals
(2.84 ,2.99)
Step-by-step explanation:
A random sample of 20 accounting students results in a mean of 2.92 and a standard deviation of 0.16
given small sample size n =20
sample mean x⁻ =2.92
sample standard deviation 'S' =0.16
level of significance ∝ = 0.95
The 95% of confidence intervals
the degrees of freedom γ=n-1 =20-1=19
t-table 2.093
![(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} },x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })](https://tex.z-dn.net/?f=%28x%5E%7B-%7D%20%20-%20t_%7B%5Calpha%20%7D%20%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%20%7D%2Cx%5E%7B-%7D%20%20%2B%20t_%7B%5Calpha%20%7D%20%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%20%7D%29)
![(2.92 - 2.093(\frac{0.16}{\sqrt{20} } ,2.92+2.093(\frac{0.16}{\sqrt{20} } )](https://tex.z-dn.net/?f=%282.92%20-%202.093%28%5Cfrac%7B0.16%7D%7B%5Csqrt%7B20%7D%20%7D%20%2C2.92%2B2.093%28%5Cfrac%7B0.16%7D%7B%5Csqrt%7B20%7D%20%7D%20%29)
(2.92-0.0748,2.92+0.0748)
(2.84 ,2.99)
Therefore the 95% of confidence intervals
(2.84 ,2.99)
Answer:
x=5
Step-by-step explanation:
First you need to combine the like terms. Add the two x-terms together and you get 8x, then subtract 8 from both sides of the equation. You now have 8x=40. Just divide each side by 8 and you end up with x=5.
Yes, It forms two right angle triangles (which are the same) because AD is the same length to DB and AC is the same length to BC. right angle triangles meet a line at 90° and thus CD must be perpendicular to AB.
Hope this helps.
Answer:
2 1/2
A.
Count the complete =2
The incomplete, a quarter + a quarter = half
Answer:
Im pretty sure the answer is A beacause all the other options seem to be wrong
Step-by-step explanation:
please mark brainliest