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3 years ago

Functions math, please help.

Mathematics

1 answer:

kozerog [31]3 years ago

8 0

Y intercept is (0,-7). slope is 2.

Change the function to y=mx+b format first. m=slope and plug in 0 as x to get y intercept.

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Joely's Tea Shop, a store that specializes in tea blends, has available 45 pounds of A grade tea and 70 pounds of B grade tea. T

prisoha [69]

Answer:

Hence, (75,40) is the maximum point and maximum profit is $192.5

Step-by-step explanation:

Let the breakfast be x

And let the lunch or afternoon be y

Inequalities will become

$\frac{1}{3}x+\frac{1}{2}y\leq 45$

$\frac{2}{3}x+\frac{1}{2}y\leq 70$

And objective function will be

Z=1.5x+2.0y

You can see the graph in the attachement

ABCD is the feasible region

Points of feasible region is (0,90) ,(0,0) ,(75,40) and(105,0)

We have to find Z by substituting the points of feasible region

At (0,90) we get

Z=1.5(0)+2(90)

Z=180

At (0,0)

Z=1.5(0)+2(0)

Z=0

At (75,40)

Z=1.5(75)+2(40)

Z=192.5

At (105,0)

Z=1.5(105)+2(0)

Z=157.5

The maximum number we are getting is 192.5 which is at (75,40)

Hence, (75,40) is the point of maximum

4 0

4 years ago

Tricia saved money, but the amount she saved didn't meet both her emergency needs and savings for her goal. Which of these would

Hoochie [10]

Tricia should take the money that she already has saved no matter how little it is and split it evenly between savings and emergency needs

6 0

4 years ago

Read 2 more answers

A population of protozoa develops with a constant relative growth rate of 0.4964 per member per day. On day zero the population

vodka [1.7K]

Answer:

The population size after eight days is about 265

Step-by-step explanation:

This is an example of an exponential growth model. A quantity <em>y</em> that grows or decays at a rate proportional to its size fits in an equation of the form

$\frac{dy}{dt}=ky$

where k is a positive constant. Its solutions have the form

$y=y_{0}e^{kt}$ ,

where $y_{0} =y(0)$ is the initial value of y.

The population size can be calculated by using the below formula:

$P(t)=P(0)e^{kt}$ where $P(0)$ is the population on day zero.

Let t be the time in days,

We know from the information given that:

k = 0.4964 per member per day and

The day zero (t = 0) the population size is 5 (P(0) = 5)

To find the population size after eight days

Substitute P(0) = 5, k=0.4964 in $P(t)=P(0)e^{kt}$

Then

$P(t)=5e^{0.4964\cdot t}$

Now we calculate P(t) when t = 8 days

$P(8) = 5e^{0.4964\cdot 8}\\P(8) = 5e^{3.9712}\\e^{3.9712}=53.04815\dots \\P(8) = 5 \cdot 53.04815\dots\\P(8) = 265.24075\dots \approx 265$

Therefore the population size after eight days is about 265

8 0

3 years ago

Help me solve this pls!!<br><br> 5+ 8 x-3=

Elden [556K]

It should be -19...!

4 0

3 years ago

What is Three less than seven

irina1246 [14]

Answer: 4

Step-by-step explanation:

7-3=4

5 0

4 years ago

Read 2 more answers

Functions math, please help.​

Functions math, please help.