15
1 answer:
Answer:
Option (E)
Step-by-step explanation:
Expression given in the attachment,
By multiplying with x on both the sides of the given equation,
x² - 15 = 2x
x² - 2x - 15 = 0
x² - 5x + 3x - 15 = 0
x(x - 5) + 3(x - 5) = 0
(x + 3)(x - 5) = 0
(x + 3) = 0
x = -3
And (x - 5) = 0
x = 5
Therefore, x = -3, 5 are the solutions of the given equation.
Option (E) will be the answer.
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Let the two numbers be x and y, then,
xy = -12 . . . (1)
x + y = -10 . . . (2)
From (2), x = -10 - y . . . (3)
Putting (3) into (1), gives
(-10 - y)y = -12
-10y - y^2 = -12
y^2 + 10y - 12 = 0
Therefore, the two numbers are
and 
xy = -12 . . . (1)
x + y = -10 . . . (2)
From (2), x = -10 - y . . . (3)
Putting (3) into (1), gives
(-10 - y)y = -12
-10y - y^2 = -12
y^2 + 10y - 12 = 0
Therefore, the two numbers are