T^2-t=12
t^2-t-12=0
(t-4)(t+3)=0
<span>t=4, -3</span>
Answer:
(f-g)(x)=7
Step-by-step explanation:
f(x)=2x
g(x)=2x-7
(f-g)(x)=f(x)-g(x)=2x-(2x-7)=7
Answer:
D
Step-by-step explanation:
Exterior means outside which means it has to be one of the angles outside the triangle.
Options A, B, and C have angles inside the triangle.
Option D is the only angle outside the triangle
We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is
. Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is
. Let's solve the first equation for x^2:
and sub that value for x^2 into the second equation.
and
. Subtract 60 from both sides and combine the y^2 terms to get
. Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it.
, x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!
Answer:
hello :
note : secy = 1 / cosy
tany = siny /cosy
sin y+cos y+tan y sin y = sin y+cos y+( siny /cosy)sin y
= ( siny cosy + cos²y + sin²y) / cosy
= (siny cosy +1) / cosy......because : cos²y+sin²y =1
= (siny cosy) / cosy + 1 / cosy
= (siny/cosy) × cosy + 1/cosy
sin y+cos y+tan y sin y = tany cosy + secy