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3 years ago

Math help please? <3

Mathematics

1 answer:

Reptile [31]3 years ago

4 0

Y - y1 = m(x - x1) is the point slope equation.
y - 9 = 3(x - -2)
(9, -2)
Letter B

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Use the figure shown. Let point D be at (-4,1) . Use the sides of triangle BDA to find the slope of the line.

gavmur [86]

The slope of the line shown in the figure having equation x + 2y = 0 is 1/2.

The point A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and Point C is at ( -2 , 2 ).

Let point D be at ( -4 , 1 ).

Now the new triangle is ΔBDA and the corner points are A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and point D is at ( -4 , 1 ).

The equation of line passing through two points is given by:

$(y-y_{1} ) = (\frac{y_{2}-y_{1} }{x_{2} - x_{1} })(x - x_{1} )$

The equation of line passing through two points A( -2 , 1 ) and B( -4 , 2 ) IS

y - 1 = ((2-1)/(-4-(-2))) (x-(-2))

y - 1 = (1/(-2)) (x+2)

2y -2 = -x -2

x + 2y = 0

The equation of straight line is x + 2y = 0

The equation in slope intercept form can be written as,

y = x/2 + 0

Slope = m = 1/2

Intercept = c = 0

So, we can conclude that 1/2 is the slope of the line .

To know more about Slope - intercept form refer to link:

brainly.com/question/1884491

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1 year ago

2) simplify the expression completely assume (x > 0)

Sati [7]

Answer:

Step-by-step explanation:

the 2 square root terms can be combined under one large square root.

and the general multiplication factor of 2 remains on the outside.

2×sqrt(24x³ / 3x) = 2×sqrt(8x²) = 2×sqrt(4×2x²) =

2×2×sqrt(2x²) = 2×2×x×sqrt(2) = 4x sqrt(2)

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3 years ago

Find the area of the surface correct to four decimal places by expressing the area in terms of a single integral and using your

love history [14]

If we substitute $x=r\cos\theta$ and $y=r\sin\theta$ , we get $r^2=x^2+y^2$ , so that

$z=\cos(x^2+y^2)=\cos(r^2)$

which is independent of $\theta$ , which in turn means the surface can be treated like a surface of revolution.

Consider the function $f(t)=\cos(t^2)$ defined over $0\le t\le1$ . Revolve the curve $C$ described by $f(t)$ about the line $t=0$ . The area of the surface obtained in this way is then

$\displaystyle2\pi\int_C\mathrm dS=2\pi\int_0^1\sqrt{1+f'(t)^2}\,\mathrm dt$

$=\displaystyle2\pi\int_0^1\sqrt{1+(-2t\sin(t^2))^2}\,\mathrm dt$

$=\displaystyle2\pi\int_0^1\sqrt{1+4t^2\sin^2(t^2)}\,\mathrm dt\approx7.4144$

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3 years ago

What is the credit-to-debit ratio on the handy hardware credit card?

olga nikolaevna [1]

The debt-to-credit ratio of a credit account is the ratio of the balance to the credit limit:

... balance/credit limit = 245.78/3500 = 0.07022... ≈ 7.02%

The appropriate choice is ...

... A.) 7.02%

7 0

3 years ago

Hi, can I send screenshot?

Sati [7]

Yes you can i think........

4 0

3 years ago

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