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3 years ago

If ΔEFG ~ ΔLMN with a ratio of 2:1, which of the following is true?

Mathematics

1 answer:

strojnjashka [21]3 years ago

7 0

Answer:

segment EF over segment LM equals segment FG over segment MN

Step-by-step explanation:

The triangles are similar, not congruent, so any answer choice with the word "congruent" can be ignored.

The sequence of letters in the triangle name tells you the corresponding segments:

EF corresponds to LM
EG corresponds to LN
FG corresponds to MN

Corresponding segments have the same ratio, so ...

EF/LM = FG/MN . . . . . . matches the first answer choice

EF/LM = EG/LN . . . . does not match the 3rd answer choice

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The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Alina [70]

we know that

Area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius

in this problem

$diameter=12\ in \\ radius=diameter/2\\ radius=12/2\\ radius=6\ in$

$A=3.14* 6^{2}$

$A=113.04 in^{2}$

therefore

the answer is the option

d. 113.04 sq. in.

8 0

3 years ago

Read 2 more answers

In a small Library there are five non-fiction books for every nine fiction book there are 130 Non-fiction books how many fiction

vova2212 [387]

Answer:

For 130 non-fiction books, the number of fiction books can be from 270 to 278.

Step-by-step explanation:

Given that, there are 5 non-fiction books for every 9 fiction books.

Observe that, if the number of fiction books is less than 9, than there will be no no-fiction books.

So, there are 5 non-fiction books for every 9 to (9+8) fiction books

So, by elementary method, there will be 5n non-fiction books for every 9n+8 fiction books, where n is a natural number.

Or, if the number of non-fiction books is 5n, then the number of fiction books will be ranging from 9n to (9n+8).

For, 150 non-fiction books, 5n=150 or n=150/5=30.

Hence, the number of fiction books can be from 9n to (9n+8).

=9x30 to (9x30+8)

=270 to 278.

Hence, for 130 non-fiction books, the number of fiction books can be from 270 to 278.

6 0

3 years ago

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.08

WINSTONCH [101]

Answer:

if 1 quarter = $ 0.25

1 dime = $ 0.10

1 penny = $ 0.01

so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar

therefore we say;

1 Quarter + 8 dimes + 3 penny

: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )

: 0.25 + 0.80 + 0.03 = $ 1.08

Now if you have a 4 Quarters, you have change for $1.

If you have 5 dimes, you have change for 2 Quarters.

If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.

If you have 5 pennies, you have enough change for 1 nickel

Therefore

(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x

(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x

x = 0.75 + 0.4 + 0.04

x = $ 1.19

PROVED

6 0

3 years ago

Please help me asap!!!

Dahasolnce [82]

Answer:

<em>P = 37 units</em>

Step-by-step explanation:

7 0

3 years ago

What theorem can you use to prove that angle GKJ is congruent angle HIK?

dmitriy555 [2]

Angle Side Angle Theorem (ASA)

The Angle Side Angle Postulate (ASA) says triangles are congruent if any two angles and their included side are equal in the triangles. An included side is the side between two angles.

4 0

3 years ago