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egoroff_w [7]
3 years ago
13

One way to inscribe an equilateral triangle in a circle is to first inscribe a(n):

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

Answer:A

Step-by-step explanation:

kupik [55]3 years ago
4 0

Answer:

A.Hexagon

...................

Thats the answer

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How many millimeters are in 1 meter? Use the metric table to help answer the question.
jeyben [28]

Answer:

100cm make one metre

10mm make 1cm

therefore, 100×10= 1000

8 0
3 years ago
Read 2 more answers
What is the value of x, such that the perimeter of the re tangle shown is at least 48
sammy [17]

Answer:

answer is 5 centimeter...

8 0
3 years ago
Find the value of x.
love history [14]

Answer:

x is 64 degrees

Step-by-step explanation:

Since the polygon is a quad we know all the angles add up to 360. So, we can do :

100 + 130 + 66 = 360 - x

296 = 360 - x

Subtract 360 on both sides

-64 =  -x

Multiply by negative one on both sides and we get

64 = x

x is 64 degrees

8 0
3 years ago
3x-6y= -12
inn [45]
There is no solution to this system of equations because they both have the same slope.

If two lines have the same slope, but are not identically the same line, then they will never intersect. There is no pair (x, y) that could satisfy both equations, because there is no point (x, y) that is simultaneously on both lines. Therefore, these equations are said to be inconsistent, and there is no solution.
5 0
3 years ago
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
4 years ago
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