Please help!!!!!! find the area of the whole rectangle.

Mathematics

1 answer:

Olegator [25]3 years ago

8 0

Answer:

Step-by-step explanation:

The area of a rec tangle is A x W

but first you have to find the area of the triangle wich is going to be 127.5.

Then you have to multiply 127.5 times 15.

And that will give you 1,912.5.

I think this is correct, but im not sure.

You might be interested in

What is the product of 2x+ 3 and 4x2 - 5x+ 6?

elena-s [515]

Answer:

8x³ - 25x² - 3x + 18

Step-by-step explanation:

(2x + 3)(4x²- 5x + 6)

multiply 2x by each of the three terms in the second expression to get:

8x³ - 10x² + 12x

now multiply 3 by each of the three terms in the second expression to get:

12x² - 15x + 18

Combine 'like terms': -10x² + (-15x²) = -25x²

Combine 'like terms': 12x + (-15x) = -3x

Put all terms in decreasing exponent order:

8x³ - 25x² - 3x + 18

7 0

3 years ago

PLEASE HELP I GIVE BRAINLIEST

Verizon [17]

Answer: B. Triangle

Step-by-step explanation:

The vertical cross-section of a pyramid is a triangle, and the horizontal cross-section of a pyramid is a square.

7 0

3 years ago

Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$