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3 years ago

Write the Quadratic equation y=x^2-6x+7

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

7 0

This is a quadratic function f(x) = y=x²-6x+7

The quadratic equation is x²-6x+7 =0

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Algebra 1 question need help !

GREYUIT [131]

At least they admitted this is algebra not geometry. You'll get the same question next year but they'll call it geometry.

The area is the product of the sides:

$A=(x-6)(3x^2-4x+6)$

We just distribute and collect terms:

$A=x(3x^2-4x+6) - 6(3x^2-4x+6)$

$A=3x^3-4x^2+6x - 18x^2 +24x -36$

$A=3x^3- 22x^2+30x-36$

Answer: 3rd choice

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3 years ago

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Order the decimals from least to greatest 48.6, 1.6, 0.13, 153.7, 2.2, 49.2

postnew [5]

Answer:

0.13, 1.6, 2.2, 48.6, 49.2, 153.7

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4 years ago

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Make x the subject. <br>1) а — x =y<br>2) m = k – x <br>3) k - t2x = m

yanalaym [24]

Answer:

${ \tt{a - x = y}} \\ \\ { \boxed{ \tt{x = a - y}}}$

${ \tt{m = k - x}} \\ \\ { \boxed{ \tt{x = k - m}}}$

${ \tt{k - {t}^{2}x = m }} \\ { \tt{ {t}^{2} x = k - m}} \\ \\ { \boxed{ \tt{x = \frac{k - m}{ {t}^{2} } }}}$

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2 years ago

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Helpp mmeee pleaseeeee !!<br> .

zmey [24]

Answer:

the answer is 6

Step-by-step explanation:

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3 years ago

Hello I need help with this immediately please see attached image thank you so much I will give Brainliest

erma4kov [3.2K]

Note that while the figure is made up of rectangle and parallelogram, then the area of this figure

$A_{figure}=A_{rectangle}+A_{parallelogram}.$

1. The area of rectangle is

$A_{rectangle\ ABCF}=AB\cdot BC.$

The vertices of rectangle are points A(-2,-2), B(0,-6), C(8,-2) and F(6,2). Then

$AB=\sqrt{(-2-0)^2+(-2+6)^2}=\sqrt{4+16}=\sqrt{20}=2\sqrt{5},\\ \\BC=\sqrt{(8-0)^2+(-2+6)^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}.$

Therefore,

$A_{rectangle\ ABCF}=2\sqrt{5}\cdot 4\sqrt{5}=8\cdot 5=40\ un.^2$

2. The area of parallelogram can be calculated using formula

$A_{parallelogram\ FCDE}=\text{base}\cdot \text{height}.$

The base of parallelogram is segment CD with length

$CD=\sqrt{(8-8)^2+(3+2)^2}=\sqrt{25}=5$

and the height has length 2 un. Then

$A_{parallelogram\ FCDE}=5\cdot 2=10\ un^2.$

3. Now

$A_{figure}=40+10=50\ un.^2$

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3 years ago