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4 years ago

How do you find the square root of something?

Mathematics

2 answers:

allochka39001 [22]4 years ago

8 0

Use the squish method. We'll use the square root of 10 as an example.

First, pick out a perfect square that is closest number that is smaller than the selected number.

In this case, this will be the number three. 3*3=9, which is one smaller than 10.

Divide 10 by 3, which is 3.33.. (round if needed)

Average the two numbers, 3.33 and 3. In this case, it is 3.166.. (again, round if needed)

Repeat and divide it by the original number. 10/3.33 is equal to <span>3.1579.

Then, average again. </span><span>The average between 3.1579 and 3.1667 is equal to 10.0001. If you want to be more precise, keep on repeating the process with the numbers.

Remember to check your work! (Also, attached is a guide for the perfect square roots of 1-100.)
</span>

ANTONII [103]4 years ago

5 0

Remember: $a = \sqrt{a}\times\sqrt{a}$

When you square root something, you have to find two same numbers that when multiplied will give you that original number.

Hope that helped :)

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4 years ago

Read 2 more answers

Which expression is equivalent to "4 times the sum of 3 and x"?

stira [4]

Answer:

D is the equivalent expression

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3 years ago

Read 2 more answers

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago

The values in the table below represent Function B, which is a linear function.

yan [13]

<h3>1. Compare Functions B and L by determining which one has the greater rate of change.</h3>

The rate of change is expressed as the ratio between a change in one variable relative to a corresponding change in another. On the other hand, a linear function is given as the form:

$y=mx+b$

And $m$ is the rate of change we are looking for. For Function B we have a Table and the slope can be found by choosing two points, therefore:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ Choosing \ (1,5) \ and \ (3,11) \\ \\ m=\frac{11-5}{3-1}=3$

As you can see $y=6x+4$ has a rate of change of 6 while the function of the table has a rate of change of 3.

<em> In conclusion,</em> $y=6x+4$ <em>has the greater rate of change</em>

<h3>2. which one has a greater y-intercept?</h3>

We need to get the equation that rules the points given on the table. Two-Point Form of the Equation of a Line is:

$y-y_{1}=m(x-x_{1}) \\ \\ We \ know \ m=3 \\ \\ y-5=3(x-1) \therefore y-5=3x-3 \therefore y=3x+2$

As you can see $y=6x+4$ has a y-intercept of $b=4$ while the function of the table has a y-intercept of $b=2$

<em> In conclusion,</em> $y=6x+4$ <em>also has the greater y-intercept</em>

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4 years ago

Anyone wanna be my friend? Also what is 1+0=?

larisa86 [58]

Answer:

Sure and its 100000000000000000000000000000

Step-by-step explanation:

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3 years ago